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Question

Mathematics Question on Complex Numbers and Quadratic Equations

Find the multiplicative inverse of 23i2 - 3i.

A

2/13+i(3/13)2/13+i(3/13)

B

2/13i(3/13)2/13-i(3/13)

C

2+3i2+3i

D

None of these

Answer

2/13+i(3/13)2/13+i(3/13)

Explanation

Solution

Let z=23iz = 2-3i , then, z1=123iz^{-1}=\frac{1}{2-3i} =2+3i(23i)(2+3i)=\frac{2+3i}{\left(2-3i\right)\left(2+3i\right)} =2+3i22(3i)2=\frac{2+3i}{2^{2}-\left(3i\right)^{2}} =2+3i13=\frac{2+3i}{13} =213+313i=\frac{2}{13}+\frac{3}{13} i