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Question: Find the modulus and amplitude of \( - 2i \) a. \( |z| = 2;amp(z) = - \dfrac{{3\pi }}{2} \) b....

Find the modulus and amplitude of 2i- 2i
a. z=2;amp(z)=3π2|z| = 2;amp(z) = - \dfrac{{3\pi }}{2}
b. z=2i;amp(z)=π2|z| = 2i;amp(z) = \dfrac{\pi }{2}
c. z=2;amp(z)=π2|z| = 2;amp(z) = \dfrac{\pi }{2}
d. z=2;amp(z)=π2|z| = 2;amp(z) = - \dfrac{\pi }{2}

Explanation

Solution

Hint : The number in the question is of the form complex number that is z=x+iyz = x + iy . The modulus of the complex number is defined as the square root of the sum of the square of the real part and the imaginary part. The complex number z=x+iyz = x + iy where x=zcosθx = |z|\cos \theta and y=zsinθy = |z|\sin \theta the θ\theta is called the amplitude of a complex number.

Complete step-by-step answer :
Consider the given number 2i- 2i . The number is a complex number which is of the form z=x+iyz = x + iy . We can write the above question as z=2iz = - 2i where x=0x = 0 and y=2y = - 2 . The modulus of the complex number is given by z=Re(z)2+Im(z)2|z| = \sqrt {\operatorname{Re} {{(z)}^2} + \operatorname{Im} {{(z)}^2}} ,where real part is x and imaginary part is y. Hence the modulus of a complex number is z=(0)2+(2)2\Rightarrow |z| = \sqrt {{{(0)}^2} + {{( - 2)}^2}}
On simplification we have
z=0+4 z=4   \Rightarrow |z| = \sqrt {0 + 4} \\\ \Rightarrow |z| = \sqrt 4 \;
Applying the square root, we have
z=2|z| = 2
Hence the modulus of the complex number 2i- 2i is 2.
Now we have to find the amplitude of the complex number 2i- 2i
Consider the given question z=2iz = - 2i . The number is a complex number which is of the form z=x+iyz = x + iy . where x=0x = 0 and y=2y = - 2 . Where x is the real part and y is the imaginary part. We can write x and y has x=zcosθx = |z|\cos \theta and y=zsinθy = |z|\sin \theta .
yx=zsinθzcosθ\Rightarrow \dfrac{y}{x} = \dfrac{{|z|\sin \theta }}{{|z|\cos \theta }}
Cancelling the like terms, we have
yx=tanθ\Rightarrow \dfrac{y}{x} = \tan \theta
And we can rewrite as, θ=tan1(yx)\Rightarrow \theta = {\tan ^{ - 1}}\left( {\dfrac{y}{x}} \right)
Therefore, the amplitude of a complex number is defined as θ=tan1(yx)\theta = {\tan ^{ - 1}}\left( {\dfrac{y}{x}} \right)
By substituting the values to the formula, we have θ=tan1(20)\Rightarrow \theta = {\tan ^{ - 1}}(\dfrac{{ - 2}}{0})
We know that any number divided by 0 is infinity
θ=tan1()\Rightarrow \theta = {\tan ^{ - 1}}( - \infty )
θ=π2\Rightarrow \theta = \dfrac{{ - \pi }}{2}
Since the point 2i- 2i lies on the negative half of the imaginary axis. So the amplitude is π2\dfrac{{ - \pi }}{2}
Hence the amplitude of 2i- 2i is π2\dfrac{{ - \pi }}{2}
Therefore, the modulus and amplitude of 2i- 2i is 2 and π2\dfrac{{ - \pi }}{2} respectively.
So, the correct answer is “Option D”.

Note : Since the given number is a complex number which contains the both real and imaginary part. We should identify the real part and imaginary part of the number and hence by using the formula we can determine the modulus and amplitude of the number.