Question
Question: Find the mode of the following frequency distribution. Class| 0 – 100| 100 – 200| 200 – 300| 300...
Find the mode of the following frequency distribution.
Class | 0 – 100 | 100 – 200 | 200 – 300 | 300 – 400 | 400 – 500 | 500 – 600 |
---|---|---|---|---|---|---|
Frequency | 64 | 62 | 77 | 62 | 66 | 54 |
Solution
We use the fact that if the data is in groups or class intervals, the modal interval corresponds to the highest frequency. We then use the formula for the mode l+2f1−f0−f2f1−f0. Substitute the values in this formula and do simplification to find the mode.
Complete step-by-step solution:
Let us write the formula of mode for grouped data.
Mode for grouped data is given as,
Mode =l+(2f1−f0−f2f1−f0)×h
Where l is the lower modal class,
h is the size of the class interval,
f1 is the frequency of modal class,
f0 is the frequency of the class preceding the modal class,
f2 is the frequency of the class succeeding the modal class,
The modal class is the interval with the highest frequency.
⇒Modal class =200−300
The lower limit of the modal class is,
⇒l=300
The class-interval is,
⇒h=300−200=100
The frequency of the modal class is,
⇒f1=77
The frequency of the class preceding the modal class is,
⇒f0=62
The frequency of the class succeeding modal class is,
⇒f2=62
Substitute these values in the mode formula,
⇒ Mode =200+2(77)−62−6277−62×100
Simplify the terms,
⇒ Mode =200+154−12415×100
Subtract the values in the denominator and multiply the terms in the numerator,
⇒ Mode =200+301500
Divide the numerator by denominator,
⇒ Mode =200+50
Add the terms,
∴ Mode =250
Hence, the mode is 250.
Note: You may mistake the mode formula with that of the median. The Median formula is given as l+f2n−cf×h. In this question, we wrote mode for grouped data. To find the mode for ungrouped data, we will find the observation which occurs the maximum number of times.