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Question: Find the median for the following frequency distribution table: Class intervals| 110-119| 120...

Find the median for the following frequency distribution table:

Class intervals110-119120-129130-139140-149150-159160-169
frequency68151065
Explanation

Solution

We find the values of class-limits and the class marks. We put all of them in a table to find the cumulative frequency. From that value we find the median class. We use the formula of median to find the solution of the problem.

Complete step by step answer:
We assume the frequencies as fi{{f}_{i}} and the class marks as xi{{x}_{i}}.
We need to find the class-limits and the class marks.
We also need to find the cumulative frequencies.
Total frequency is n=6+8+15+10+6+5=50n=6+8+15+10+6+5=50. So, n2=502=25\dfrac{n}{2}=\dfrac{50}{2}=25.
From the cumulative frequency we can find the median class will be 129.5-139.5.

class intervalsclass limitsclass marks (xi{{x}_{i}})frequency (fi{{f}_{i}})cumulative frequency (Fi{{F}_{i}})
110-119109.5-119.5114.566
120-129119.5-129.5124.5814
130-139129.5-139.5134.51529
140-149139.5-149.5144.51039
150-159149.5-159.5154.5645
160-169159.5-169.5164.5550
Totaln=50n=50

We also the formula of median as median(xi)=l+n2Flfme×cmedian\left( {{x}_{i}} \right)=l+\dfrac{\dfrac{n}{2}-{{F}_{l}}}{{{f}_{me}}}\times c.
Here l is the lower limit of the median class. Fl{{F}_{l}} denotes the cumulative frequency of the previous class of that median class. fme{{f}_{me}} denotes the frequency of the median class. Also, c is the class width of the frequency table. In our problem the value of c is 10.
So, we put the values in the equation and get
median(xi)=l+n2Flfme×c=129.5+5021415×10median\left( {{x}_{i}} \right)=l+\dfrac{\dfrac{n}{2}-{{F}_{l}}}{{{f}_{me}}}\times c=129.5+\dfrac{\dfrac{50}{2}-14}{15}\times 10
We solve this equation to get the value of median.
So, median(xi)=129.5+5021415×10=129.5+11015=129.5+7.33=136.83median\left( {{x}_{i}} \right)=129.5+\dfrac{\dfrac{50}{2}-14}{15}\times 10=129.5+\dfrac{110}{15}=129.5+7.33=136.83
The median value of the given frequency distribution table is 136.83.

Note:
We need to remember the median is the value of the frequency being at the most middle point. So, instead of finding mean we use the formula of median as it considers the density of a cumulative grouped data. We need to be careful finding the median class.