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Question

Question: Find the mean of first n natural numbers....

Find the mean of first n natural numbers.

Explanation

Solution

Hint:Mean can be calculated by dividing sum of numbers (observation) by number of observations.
For example, if your class has 3 students and they scored 60, 70, 80 marks respectively.
Average marks that your class has scored is:
Mean = Sum of all numbersNo. of observation\dfrac{{{\text{Sum of all numbers}}}}{{{\text{No}}{\text{. of observation}}}}
= 60+70+803\dfrac{{60 + 70 + 80}}{3}
= 2103\dfrac{{210}}{3}
= 70

Complete step-by-step answer:

Now coming to the exact question, here we have two calculate the mean of first n natural numbers.
If we want to calculate mean of first n natural numbers:
First n natural numbers = 1, 2, 3, 4,5 ……………. n
Sum of n natural numbers = (1+2+3+……+n) (Eq 1)
= n(n+1)2\dfrac{{{\text{n}}({\text{n}} + 1)}}{2} (Eq 2)
Total no. of observations = n
Now, we know that
Mean = Sum of all numbersNo. of observation\dfrac{{{\text{Sum of all numbers}}}}{{{\text{No}}{\text{. of observation}}}}.
Putting the values from equation 1 and 2, we get:
Mean =1+2+3+.....+nn\dfrac{{1 + 2 + 3 + ..... + {\text{n}}}}{{\text{n}}}
= n(n+1)2×n\dfrac{{{\text{n}}({\text{n}} + 1)}}{{2 \times {\text{n}}}}
= (n+1)2\dfrac{{(n + 1)}}{2}

Therefore, we can write:
Mean of first n natural numbers = (n+1)2\dfrac{{(n + 1)}}{2}

Note: In this type of question, first, we should remember the formula to find the sum of n natural numbers which is given as ; S= n(n+1)2\dfrac{{n(n + 1)}}{2}. After this to find the mean, you have to divide the sum by the total number of entities, which is n in this case.