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Question

Mathematics Question on Mean Deviation

Find the mean deviation about the median for the data.

xix_i579101215
fif_i862226
Answer

The given observations are already in ascending order.

Adding a column corresponding to cumulative frequencies of the given data, we obtain the following table

xix_ifif_ic.fc.f
588
7614
9216
10218
12220
15626

Here, N = 26, which is even.

Median is the mean of 13th and 14th observations. Both of these observations lie in the cumulative frequency 14, for which the corresponding observation is 7.

Median,M= 13thobservation+1414observation2=7+72=7\frac{\frac13^{th}observation+14^{14}observation}{2}=\frac{7+7}{2}=7

The absolute values of the deviations from median, i.e xiM,|x_i-M|, are

xi,M|x_i,M|| 2| 0| 2| 3| 5| 8
---|---|---|---|---|---|---
fif_i| 8| 6| 2| 2| 2| 6
fixiMf_i|x_iM|| 16| 0| 4| 6| 10| 48

I=16fi=26\sum_{I=1}^{6}f_i=26 and I=16fixiM=84\sum_{I=1}^{6}f_i|x_i-M|=84

=MD(M)=1Ni=16fixiM=126X84=3.23=MD(M)=\frac{1}{N}\sum_{i=1}^{6}f_i|x_i-M|=\frac{1}{26}X84=3.23