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Question

Mathematics Question on Variance and Standard Deviation

Find the mean and variance for the following frequency distribution.

Classes0-1010-2020-3030-4040-50
Frequencies5815166
Answer
ClassFrequency fif_imidpointximid-point\,x_iyi=xi2510y_i=\frac{x_i-25}{10}yi2y_i^2fiyif_iy_ifiy12f_iy_1^2
0-1055-24-1020
10-20815-11-88
20-3015250000
30-401635111616
40-506452121224
501068

Mean, xˉ=Ai=15fixin×h=25+1050×10=25+2=27\bar{x}=A\frac{\sum_{i=1}^5f_ix_i}{n}×h=25+\frac{10}{50}×10=25+2=27

Variance (σ2) = h2N2[Ni=15fiyi2(i=15fiyi)2]\frac{h^2}{N^2}[N\sum_{i=1}^5f_iy_i^2-(\sum_{i=1}^5f_iy_i)^2]

=(10)2(50)2[50×68(10)2]=\frac{(10)^2}{(50)^2}[50×68-(10)^2]

125[3400100]=330025\frac{1}{25}[3400-100]=\frac{3300}{25}

=132=132