Question
Mathematics Question on Variance and Standard Deviation
Find the mean and variance for the following frequency distribution.
Classes | 0-30 | 30-60 | 60-90 | 90-120 | 120-150 | 150-180 | 180-210 |
---|---|---|---|---|---|---|---|
Frequencies | 2 | 3 | 5 | 10 | 3 | 5 | 2 |
Answer
Class | Frequency fi | mid−pointxi | yi=30xi−105 | fiyi | yi2 | fiy12 |
---|---|---|---|---|---|---|
0-30 | 2 | 15 | -3 | -6 | 9 | 18 |
30-60 | 3 | 45 | -2 | -6 | 4 | 12 |
60-90 | 5 | 75 | -1 | -5 | 1 | 5 |
90-120 | 10 | 105 | 0 | 0 | 0 | 0 |
120-150 | 3 | 135 | 1 | 3 | 1 | 3 |
150-180 | 5 | 165 | 2 | 10 | 4 | 20 |
180-210 | 2 | 195 | 3 | 6 | 9 | 18 |
30 | 2 | 76 |
Mean, xˉ=An∑i=17fixi×h=105+302×30=105+2=107
Variance(σ2) = N2h2[N∑i=17fiyi2−(∑i=17fiyi)2]
=(30)2(30)2[30×76−(2)2]
=2280−4
=2276