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Question

Mathematics Question on Variance and Standard Deviation

Find the mean and variance for the following frequency distribution.

Classes0-3030-6060-9090-120120-150150-180180-210
Frequencies23510352
Answer
ClassFrequency fif_imidpointximid-point\,x_iyi=xi10530y_i=\frac{x_i-105}{30}fiyif_iy_iyi2y_i^2fiy12f_iy_1^2
0-30215-3-6918
30-60345-2-6412
60-90575-1-515
90-120101050000
120-15031351313
150-1805165210420
180-210219536918
30276

Mean, xˉ=Ai=17fixin×h=105+230×30=105+2=107\bar{x}=A\frac{\sum_{i=1}^7f_ix_i}{n}×h=105+\frac{2}{30}×30=105+2=107

Variance(σ2) = h2N2[Ni=17fiyi2(i=17fiyi)2]\frac{h^2}{N^2}[N\sum_{i=1}^7f_iy_i^2-(\sum_{i=1}^7f_iy_i)^2]

=(30)2(30)2[30×76(2)2]=\frac{(30)^2}{(30)^2}[30×76-(2)^2]

=22804=2280-4

=2276=2276