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Question

Mathematics Question on Applications of Derivatives

Find the maximum profit that a company can make, if the profit function is given by p(x) = 41−24x−18x2

Answer

The profit function is given as p(x) = 41−24x−18x2.

p'(x)=-24-36x

p''(x)=-36

Now,

p'(x)=0=x=-2436-\frac{24}{36}=23-\frac{2}{3}

Also,

p'(23-\frac{2}{3})=-36<0

By second derivative test,x=23-\frac{2}{3} is the point of local maxima of p.

= Maximunm profit =p(23-\frac{2}{3})

=41-24(23-\frac{2}{3})-18(23-\frac{2}{3})2

=41+16-8

=49

Hence, the maximum profit that the company can make is 49 units.