Question

Find the mass of silver deposited when a current of 1.5 ampere passes through silver nitrate solution for five minutes. (Atomic mass of $Ag$ is 108 g)

Answer 1

Silver is a chemical element represented by the symbol $Ag$ and the word silver is taken from Latin which has the meaning shiny or white and silver is a soft, white and lustrous transition metal having atomic number 47.

Complete step-by-step answer: Molar mass of silver is 108$gmo{{l}^{-1}}$ and we know 1 Farad = 96500 C
Charge represented by the symbol Q is given by the multiplication of current with time
$Q=i\times t$
The value of i and t is given in the question, now put the values in the above formula
$Q=1.5\times 5\times 60=450C$; Time is given in minutes so multiply it with 60 to convert in seconds.
Weight of the substance deposited = ZQ
Where Z is given by $\dfrac{M}{nF}$; M is molar mass of silver 108$gmo{{l}^{-1}}$, n-factor of silver nitrate is 1 and F = 96500 C
By putting the value $Z=\dfrac{108}{1\times 96500}$
Then weight of the substance = $=\dfrac{108}{1\times 96500}\times 450$= 0.5 gm.
Hence we can say that the mass of silver deposited when a current of 1.5 ampere passes through silver nitrate solution for five minutes is 0.5 gm.

Note: Molar mass of a chemical compound is defined as the mass of a sample of the compound divided by the amount of substance in that sample which is measured in moles i.e. Molar mass (M) = $\dfrac{m}{n}$; m = mass of substance and n = number of moles.