Solveeit Logo

Question

Physics Question on Moving charges and magnetism

Find the magnetic field at point PP due to a straight line segment ABAB of length 6cm6\, cm carrying a current of 5A5\, A. (See figure) (μ0=4π×107NA2)\mu_0 \, = \, 4\pi \times \, 10^{-7} \, N-A^{-2})

A

3.0×105T3.0 \times 10^{-5} T

B

2.5×105T2.5 \times 10^{-5} T

C

2.0×105T2.0 \times 10^{-5} T

D

1.5×105T1.5 \times 10^{-5} T

Answer

1.5×105T1.5 \times 10^{-5} T

Explanation

Solution

b=μ0I4πd2sinθb \, = \, \frac{\mu_0 I}{4 \pi d} \, 2 sin \theta
d = 4 cm
sinθ=35sin \theta \, = \, \frac{3}{5}