Question
Mathematics Question on Prime and Composite Numbers
Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
Answer
L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore, the required number = 90 + 5 = 95
Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore, the required number = 90 + 5 = 95