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Question

Mathematics Question on Square Roots of Decimals

Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained.

  1. 402
  2. 1989
  3. 3250
  4. 825
  5. 4000
Answer

(i) The square root of 402402 can be calculated by long division method as follows.

| 20
---|---
2| 4ˉ0ˉ2ˉ\bar4\bar0\bar2
4-4
4| 02
00
| 2

The remainder is 22.
It represents that the square of 2020 is less than 402402 by 22.
Therefore, a perfect square will be obtained by subtracting 22 from the given number 402402.
Therefore, required perfect square = 4022=400402 - 2 = 400
And, 400=20\sqrt{400} = 20


(ii) The square root of 19891989 can be calculated by long division method as follows.

| 44
---|---
4| 1ˉ9ˉ8ˉ9ˉ\bar1\bar9\bar8\bar9
16-16
84| 389
336
| 53

The remainder is 5353.
It represents that the square of 4444 is less than 19891989 by 5353.
Therefore, a perfect square will be obtained by subtracting 5353 from the given number 19891989.
Therefore, required perfect square = 198953=19361989 - 53 = 1936
And, 1936=44\sqrt{1936} = 44


(iii) The square root of 32503250 can be calculated by long division method as follows.

| 57
---|---
5| 3ˉ2ˉ5ˉ0ˉ\bar3\bar2\bar5\bar0
25-25
107| 750
749
| 1

The remainder is 11.
It represents that the square of 5757 is less than 32503250 by 11.
Therefore, a perfect square can be obtained by subtracting 11 from the given number 32503250.
Therefore, required perfect square = 32501=32493250 - 1 = 3249
And, 3249=57\sqrt{3249} = 57


(iv) The square root of 825 825 can be calculated by long division method as follows.

| 28
---|---
2| 8ˉ2ˉ5ˉ\bar8\bar2\bar5
-4
48| 425
384
| 41

The remainder is 4141.
It represents that the square of 2828 is less than 825825 by 4141.
Therefore, a perfect square can be calculated by subtracting.


(v) 40004000 We know that, if we subtract the remainder from the number, we get a perfect square.

| 63
---|---
6| 4ˉ0ˉ0ˉ0ˉ\bar4\bar0\bar0\bar0
36-36
123| 400
-369
| 31

Here, we get remainder 3131.
Therefore 3131 must be subtracted from 40004000 to get a perfect square.
\therefore 400031=39694000 – 31 = 3969