Question
Physics Question on Dual nature of radiation and matter
Find the kinetic energy of the fastest emitted electron if an ultraviolet ray of 6.2 falls on the aluminum surface, the work function given is 4.2 eV
Answer
To find the kinetic energy of the fastest emitted electron, we can use the equation:
Kinetic Energy = Energy of Incident Photon - Work Function
Given:
The energy of Incident Photon = 6.2 eV
Work Function of Aluminum = 4.2 eV
Substituting these values into the equation, we have:
Kinetic Energy = 6.2 eV - 4.2 eV
Calculating the difference, we get:
Kinetic Energy = 2.0 eV
Therefore, the kinetic energy of the fastest emitted electron is 2.0 electron volts (eV).