Find the height above the surface of the earth where weight... | PHYSICS - ACCELERARTION DUE TO GRAVITY OF THE EARTH | SolveeIt | Solveeit

Today, August 18

Question

Find the height above the surface of the earth where weight becomes half.

A

$\frac{R}{2}$

B

(√2 - 1)R

C

$\frac{R}{\left( \sqrt{2} + 1 \right)}$

D

$\frac{R}{\sqrt{2}}$

Answer

(√2 - 1)R

Explanation

Solution

$\frac{1}{2} = \frac{1}{\left( 1 + \frac{h}{R} \right)^{2}}orh = \left( \sqrt{2} - 1 \right)R$