Question
Question: Find the general solution of sin2x + cosx = 0...
Find the general solution of sin2x + cosx = 0
Solution
Hint: First we will use the trigonometric formula sin2x=2sinxcosx , and then we will take the term cosx common and then use the formula for finding the general solution of two different equations and that will be the answer.
Complete step-by-step answer:
Let’s start solving the question,
sin2x + cosx = 0
Now we will use sin2x=2sinxcosx , to expand sin2x and then we will take cosx common.
2sinxcosx+cosx=0cosx(2sinx+1)=0
Now we have converted it into two equation and we will solve it separately,
cosx = 0 and 2sinx + 1 = 0
Let’s first solve cosx = 0,
We know that cos2π = 0,
Hence, we can say that cosx = cos2π.
Now we will use the formula for general solution of cos,
Now, if we have cosθ=cosα then the general solution is:
θ=2nπ±α
Now using the above formula for cosx = cos2π we get,
x=2nπ±2π............(1)
Here n = integer.
Now we will find the general solution of 2sinx + 1 = 0
sinx=2−1sinx=sin6−π
Now we will use the formula for general solution of sin,
Now, if we have sinθ=sinα then the general solution is:
θ=nπ+(−1)nα
Now using the above formula for sinx=sin6−π we get,
x=nπ+(−1)n(6−π).............(2)
Here n = integer.
Now from equation (1) and (2) we can say that the answer is,
x=2nπ±2π or x=nπ+(−1)n(6−π)
Hence, this is the answer to this question.
Note: The trigonometric formula sin2x=2sinxcosx that we have used must be kept in mind. One can also take some different value of α like in cosx = 0 we can take 23π instead of 2π , and then can apply the same formula for the general solution and the answer that we get will also be correct.