Question
Question: Find the general solution of cos4x = cos2x...
Find the general solution of cos4x = cos2x
Solution
Hint: First we will rearrange the given equation of taking the variable x to one side and after that we will use the trigonometric formula cosC−cosD=−2sin(2C+D)sin(2C−D) , and then we will use the formula for finding the general solution of two different equation of sin, and that will be the answer.
Complete step-by-step answer:
Let’s start solving the question.
cos4x=cos2xcos4x−cos2x=0
Now using the formula cosC−cosD=−2sin(2C+D)sin(2C−D) we get,
−2sin(24x+2x)sin(24x−2x)=0
−2sin3xsinx=0
From this we get two equations,
sin3x=0 or sinx=0
Let’s first solve for sin3x = 0,
We know that sin0 = 0,
Therefore we get,
sin3x = sin0
Now, if we have sinθ=sinα then the general solution is:
θ=nπ+(−1)nα
Now using the above formula for sin3x = sin0 we get,
3x=nπ+(−1)n0x=3nπ..........(1)
Now we will solve sinx = 0,
We know that sin0 = 0,
Therefore we get,
sinx = sin0
Now, if we have sinθ=sinα then the general solution is:
θ=nπ+(−1)nα
Now using the above formula for sin3x = sin0 we get,
x=nπ+(−1)n0x=nπ..........(2)
Now from equation (1) and (2) we can say that the answer is,
x=3nπ or x=nπ
Hence, this is the answer to this question.
Note: The trigonometric formula cosC−cosD=−2sin(2C+D)sin(2C−D) and the formula for general solution of sin must be kept in mind. In this question we can also take the value of α as π , and then use the formula of general solution to find the answer, the answer that we get is also correct, so if there are multiple options then one can make a mistake thinking that only one answer is correct.