Solveeit Logo

Question

Question: Find the general solution for tanx = \(\sqrt{3}\)...

Find the general solution for tanx = 3\sqrt{3}

Explanation

Solution

Hint: First we will write that for what value of tan of the angle we get 3\sqrt{3} , and then we will use the general solution of tan to find all the possible solutions, and we can see that there will be infinitely many solutions of x for which it gives tanx = 3\sqrt{3} .
Complete step-by-step answer:
Let’s start solving the question.
Let’s first find the value of angle for which we get 3\sqrt{3}.
Now we need to find that at which quadrant tan is positive,
We know that tan is positive in 3rd{3}^{rd} and 1st{1}^{st} quadrant, so π3\dfrac{\pi }{3} and π+π3\pi +\dfrac{\pi }{3} both are the correct value,
Here, we will take π3\dfrac{\pi }{3}.
Now we know that tanπ3=3\tan \dfrac{\pi }{3}=\sqrt{3}
Hence, we get tanx=tanπ3\tan x=\tan \dfrac{\pi }{3}
Now we will use the formula for general solution of tan,
Now, if we have tanθ=tanα\tan \theta =\tan \alpha then the general solution is:
θ=nπ+α\theta =n\pi +\alpha
Now using the above formula for tanx=tanπ3\tan x=\tan \dfrac{\pi }{3} we get,
x=nπ+π3x=n\pi +\dfrac{\pi }{3}
Here n = integer.
Hence, from this we can see that we will get infinitely many solutions for x as we change the value of n.

Note: The formula for finding the general solution of tan is very important and must be kept in mind.
In the above solution we have taken the value of α\alpha we have taken wasπ3\dfrac{\pi }{3} , but one can also take the value of α\alpha as 4π3\dfrac{4\pi }{3} , as it lies in the 3rd{3}^{rd} quadrant and gives positive value for tan. And then one can use the same formula for a general solution and replace the value of α\alpha with 4π3\dfrac{4\pi }{3} to get the answer, which is also correct.