Question

Find the following integral: $\int \sec x(\sec x +\tan x)dx$

Answer 1

$\int \sec x(\sec x +\tan x)dx$

= $\int (\sec^2 x +\sec x \tan x)dx$

= $\int \sec^2 xdx + \int \sec x \tan x dx$

= $\tan x + \sec x +C$