Question

Find the following integral: $\int \frac{2-3 \sin x}{\cos^2 x}dx$

Answer 1

$\int \frac{2-3 \sin x}{\cos^2 x}dx$

= $\int \bigg(\frac{2}{\cos^2 x}-\frac{3 \sin x}{\cos^2 x}\bigg)dx$

= $\int 2\sec^2 xdx - 3\int \tan x\sec xdx$

= $2 \tan x -3\sec x+C$