Question

Find the following integral: $\int(4e^{3x}+1)dx$

Answer 1

$\int(4e^{3x}+1)dx$

= $4\int e^{3x}dx+\int 1dx$

= $4\bigg(\frac{e^{3x}}{3}\bigg)+x+C$

= $\frac{4}{3}e^{3x}+x+C$