Question
Mathematics Question on integral
Find the following integral: ∫(2x−3cosx+ex)dx
Answer
∫(2x−3cosx+ex)dx
= 2∫xdx−3cosxdx+∫exdx
=22x2−3(sinx)+ex+C
= x2−3sinx+ex+C
Find the following integral: ∫(2x−3cosx+ex)dx
∫(2x−3cosx+ex)dx
= 2∫xdx−3cosxdx+∫exdx
=22x2−3(sinx)+ex+C
= x2−3sinx+ex+C