Question
Mathematics Question on integral
Find the following integral: ∫(2x2−3sinx+5x)dx
Answer
∫(2x2−3sinx+5x)dx
= 2∫x2dx−3∫sinxdx+5∫x21dx
= 32x3−3(−cosx)+5(23x23)+C
=32x3+3cosx+310x23+C
Find the following integral: ∫(2x2−3sinx+5x)dx
∫(2x2−3sinx+5x)dx
= 2∫x2dx−3∫sinxdx+5∫x21dx
= 32x3−3(−cosx)+5(23x23)+C
=32x3+3cosx+310x23+C