Question

Find the equivalent capacitance between A & B. If C = 16 µF

• A. 48 m φ
• B. 64m φ
• C. 8 m φ
• D. 16 m φ

Answer 1

Answer: (D)

16 µF

Answer 2

Solution:

1. Step 1: Series Combination

   For two identical capacitors $C = 16\,\mu F$ in series, the equivalent capacitance is

   $$C_s = \frac{C}{2} = \frac{16}{2} = 8\,\mu F.$$

2. Step 2: Parallel Combination

   The circuit consists of two such series combinations arranged in parallel. Thus,

   $$C_{eq} = C_s + C_s = 8\,\mu F + 8\,\mu F = 16\,\mu F.$$

Short Explanation:

• Two $16\,\mu F$ capacitors in series give $8\,\mu F$.
• Two series combinations in parallel add up: $8 + 8 = 16\,\mu F$.