Question
Question: Find the equation of the parabola having the vertex at \( \left( {0,1} \right) \) and the focus at \...
Find the equation of the parabola having the vertex at (0,1) and the focus at (0,0) :
A. x2+4y−4=0
B. x2+4y+4=0
C. x2−4y+4=0
D. x2−4y−4=0
Solution
Hint : Take the general equation of the parabola and then substitute the values of the vertex. Calculate the value of a by taking the distance of the vertex from the focus and then substitute in the equation of parabola.
Complete step-by-step answer :
As given in the question, the parabola has the vertex at (0,1) and the focus at (0,0) . The focus lies below the vertex. So, the general equation of the parabola is (x−h)2=−4a(y−k) where (h,k) is the vertex of the parabola and a is the distance between the vertex and the focus.
Substitute 0 for h and 1 for k in the equation of parabola as per given in the question:
(x−h)2=−4a(y−k) (x−0)2=−4a(y−1) x2=−4a(y−1)…(1)
Now calculate the distance between the vertex (0,1) and focus (0,0) by using the distance formula.
(0−0)2+(0−1)2=02+(−1)2 =1 =1
As the value of a is the distance of the focus from the vertex which is equal to 1 .
Substitute 1 for a in the equation (1) of parabola.
x2=−4a(y−1) x2=−4(1)(y−1) x2=−4y+4 x2+4y−4=0
So, the equation of the parabola is equal to x2+4y−4=0 .
So, the correct answer is “Option A”.
Note : The general equation of the parabola with focus below the vertex is equal to (x−h)2=−4a(y−k) where (h,k) is the vertex of the parabola and a is the distance between the vertex and the focus. The distance between two points (x1,y1) and (x2,y2) is equal to (x2−x1)2+(y2−y1)2 with the help of the distance formula in two dimensional geometry.