Question

Find the equation of the line which passes through the point (-4, 3) with slope $\frac 12$.

Answer 1

We know that the equation of the line passing through point (x0, y0), whose slope is m, is:
$(y-y_0)=m(x-x_0) .$
Thus, the equation of the line passing through point (-4, 3), whose slope is $\frac 12$, is:
$(y-3) = \frac 12(x+4)$
$2(y-3) = x+4$
$2y-6 = x+4$
$x-2y+10 = 0$