Question
Mathematics Question on Three Dimensional Geometry
Find the equation of the line that passes through the point(1,2,3)and is parallel to the vector 3i^+2j^-2k^.
Answer
It is given that the line passes through the point A(1,2,3).
Therefore, the position vector through A is
a=i^+2j^+3k^, b=3i^+2j^-2k^
It is known that the line that passes through point A and is parallel to b is given by r=a+λb, where λ is a constant.
⇒i^+2j^+3k^+λ+(3i^+2j^-2k^)
This is the required equation of the line.