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Question

Mathematics Question on Hyperbola

Find the equation of the hyperbola satisfying the give conditions: Vertices (±2, 0), foci (±3, 0)

Answer

Vertices (±2, 0), foci (±3, 0)
Here, the vertices are on the x-axis.

Therefore, the equation of the hyperbola is of the form x2a2y2b2=1\frac{x^2}{a^2} –\frac{ y^2}{b^2} = 1.
Since the vertices are (±2, 0), a = 2.
Since the foci are (±3, 0), c = 3.

We know that a2+b2=c2.a ^2 + b^ 2 = c^ 2.

22\+b2=32∴ 2^2 \+ b^2 = 3^2
b2=94=5b^2 = 9 – 4 = 5

∴ The equation of the hyperbola is x24y25=1\frac{x^2}{4} –\frac{ y^2}{5} = 1