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Question

Mathematics Question on Ellipse

Find the equation for the ellipse that satisfies the given conditions b=3b =3, c=4c =4, center at the origin; foci on the xaxis.x-axis.

Answer

It is given that b=3,b= 3, c=4c = 4, center at the origin; foci on the xaxis.x-axis.
Since the foci are on the xaxisx-axis, the major axis is along the xaxis.x-axis.
Therefore, the equation of the ellipse will be of the form x2a2\+y2b2=1\dfrac{x^2}{a^2} \+ \dfrac{y^2}{b^2} = 1, where a is the semi-major axis.
Accordingly, b=3b = 3, c=4.c= 4.
It is known that

a2=b2\+c2a^2 = b^2 \+ c^2

a2=32\+42∴ a^2 = 3^2 \+ 4^2
a2=25⇒a^2=25
a=25⇒a = √25
a=5⇒a= 5

Thus, the equation of the ellipse is x252\+y232=1\dfrac{x^2}{5^2} \+ \dfrac{y^2}{3^2}=1 or x225+y29=1\dfrac{x^2}{25} +\dfrac{y^2}{9} = 1