Solveeit Logo

Question

Mathematics Question on Ellipse

Find the equation for the ellipse that satisfies the given conditions: Foci (±3,0),(±3,0), a=5a=5

Answer

Gven that, foci (±3,0)( ±3, 0), a=4a= 4
Since the foci are on the xaxisx-axis, the major axis is along the xaxisx-axis
Therefore, the equation of the ellipse will be of the form x2a2+y2b2=1\dfrac{x^2}{a^2} +\dfrac{ y^2}{b^2} = 1, where aa is the semi-major axis.
Accordingly, c=3c = 3 and a=4a = 4.
It is known that

a2=b2\+c2a^2 = b^2 \+ c^2

42=b2\+32∴ 4^2 = b^2 \+ 3^2

16=b2\+9⇒ 16 = b^2 \+ 9

b2=169⇒ b^2 = 16 – 9

b2=7⇒ b^2 = 7

Thus, the equation of the ellipse is x216+y27=1\dfrac{x^2}{16} + \dfrac{y^2}{7} = 1