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Question

Mathematics Question on Ellipse

Find the equation for the ellipse that satisfies the given conditions: Ends of major axis(0,±√5) ends of minor axis ( ±1,0)

Answer

Given that, the ends of the major axis(0,±5) (0, ±√5) , ends of minor axis (±1,0)( ±1, 0)
Here, the major axis is along the yaxis.y-axis.
Therefore, the equation of the ellipse will be of the form x2b2+y2a2=1\dfrac{x^2}{b^2}+ \dfrac{y^2}{a^2} = 1, where ‘a’ is the semi-major axis.

Accordingly, a = √5 and b = 1.

∴ The equation for the ellipse x212+y2(5)2=1\dfrac{x^2}{1^2}+ \dfrac{y^2}{(√5)^2} = 1or x21+y25=1\dfrac{x^2}{1}+ \dfrac{y^2}{5} = 1 (Ans)