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Question

Mathematics Question on Ellipse

Find the equation for the ellipse that satisfies the given conditions: Ends of major axis (±3,0)(±3,0) ends of the minor axis (0,±2)(0,±2)

Answer

Given that , the ends of the major axis (±3,0)( ±3, 0), ends of minor axis (0,±2)(0, ±2) $$
Here, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the formx2a2\+y2b2=1 \dfrac{x^2}{a^2} \+ \dfrac{y^2}{b^2} = 1, where ‘a’ is the semi-major axis.
Accordingly, a=3a = 3 and b=2.b = 2.
Thus, the equation of the ellipse is x232\+y222=1 \dfrac{x^2}{3^2} \+ \dfrac{y^2}{2^2} = 1 or x29\+y24=1 \dfrac{x^2}{9} \+ \dfrac{y^2}{4} = 1. (Ans)