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Question: Find the elasticity of supply for supply function\(x = 2{p^2} + 5\), when \(p = 3\). A. \(\dfrac{{...

Find the elasticity of supply for supply functionx=2p2+5x = 2{p^2} + 5, when p=3p = 3.
A. 2336\dfrac{{23}}{{36}}
B. 3623\dfrac{{36}}{{23}}
C. 6332\dfrac{{63}}{{32}}
D. None of these

Explanation

Solution

Hint : We will differentiate the value of xxwith respect to pp.Further we will use the formula of elasticity of supply to get the answer. By using the formula for elasticity of supply=changeinsupplyactualsupply×actualpricechangeinprice = \dfrac{{change\,in\,\,su\,pply}}{{actual\,su\,pply}} \times \dfrac{{\,\,\,\,actual\,price\,\,\,\,}}{{change\,in\,price}}.

Complete step-by-step answer :
The given supply function
x=2p2+5x = 2{p^2} + 5
We will do differentiate the value of xxwith respect to pp,we have
dxdp=2×2p\dfrac{{dx}}{{dp}} = 2 \times 2p
dxdp=4p\dfrac{{dx}}{{dp}} = 4p
By using the formula of Elasticity of supply, we will get
Elasticity of supply=dxdp×px = \dfrac{{dx}}{{dp}} \times \dfrac{p}{x}
Elasticity of supply =4p×p2p2+5 = 4p \times \dfrac{p}{{2{p^2} + 5}}
Elasticity of supply =4p22p2+5 = \dfrac{{4{p^2}}}{{2{p^2} + 5}} (i)\left( i \right)
We will put the value of p, p=3p = 3in equation(i)\left( i \right),we have
Elasticity of supply=4(3)22(3)2+5 = \dfrac{{4{{\left( 3 \right)}^2}}}{{2{{\left( 3 \right)}^2} + 5}}
Elasticity of supply =3623 = \dfrac{{36}}{{23}}
So, the correct answer is “Option B”.

Note : Elasticity of supply is the degree of responsiveness of quantity supplied to a change in price. The elasticity of supply establishes a quantitative relationship between the supply of a commodity and its price.