Solveeit Logo
Login

Question

Question: Find the distance of centre of mass of \({{\text{H}}_{\text{2}}}{\text{O}}\) molecule....

Find the distance of centre of mass of H2O{{\text{H}}_{\text{2}}}{\text{O}} molecule.

Explanation

Solution

In order to solve this question, it is necessary to know the structure H2O{{\text{H}}_{\text{2}}}{\text{O}} molecule. The mass of one hydrogen atom is 1 unit and the mass of an oxygen atom is 16 units. Using these data, the centre of mass can be calculated.
Formula Used: The formulae used in the solution are given here.
XCM=m1x1+m2x2+m3x3m1+m2+m3{X_{CM}} = \dfrac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}}, YCM=m1+m2y2+m3y3m1+m2+m3{Y_{CM}} = \dfrac{{{m_1} + {m_2}{y_2} + {m_3}{y_3}}}{{{m_1} + {m_2} + {m_3}}}.

Complete Step by Step Solution: The H2O{{\text{H}}_{\text{2}}}{\text{O}} molecule is formed by the two hydrogen atoms and an oxygen atom. The mass of one hydrogen atom is 1 unit and the mass of an oxygen atom is 16 units.
The structure is in the form of a triangle, with the oxygen atom forming the apex of the triangle and the angle between the two O−HO - H bonds, the two arms of the triangle is 104∘{104^ \circ }.
The distance between the hydrogen atom and oxygen atom is 0.96×10 - 10m{\text{0}}{{.96 \times 1}}{{\text{0}}^{{\text{ - 10}}}}{\text{m}}.
By the formula of Centre of Mass, XCM=m1x1+m2x2+m3x3m1+m2+m3{X_{CM}} = \dfrac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}}.
Using the values we have in the above formula, we have, XCM=−dsin⁡52∘+dsin⁡52∘+16×01+1+16=0{X_{CM}} = \dfrac{{ - d\sin {{52}^ \circ } + d\sin {{52}^ \circ } + 16 \times 0}}{{1 + 1 + 16}} = 0
YCM=m1+m2y2+m3y3m1+m2+m3{Y_{CM}} = \dfrac{{{m_1} + {m_2}{y_2} + {m_3}{y_3}}}{{{m_1} + {m_2} + {m_3}}}.
Using the values we have in the above formula, we have,YCM=0+0+16×0.96×10−10cos⁡52∘1+1+16=89×0.96×10−10cos⁡52∘=6.4×10−12m{Y_{CM}} = \dfrac{{0 + 0 + 16 \times 0.96 \times {{10}^{ - 10}}\cos {{52}^ \circ }}}{{1 + 1 + 16}} = \dfrac{8}{9} \times 0.96 \times {10^{ - 10}}\cos {52^ \circ } = 6.4 \times {10^{ - 12}}m.

Centre of mass of a water molecule is 0,6.4×10−120,6.4 \times {10^{ - 12}}.

Note: In this question we have the answer in form of coordinates, it means the centre of mass is at a distance of 6.4×10−12m6.4 \times {10^{ - 12}}m away from the centre of the line joining the two hydrogen atom.One interesting fact about the water molecule is that is forms hydrogen bond, which is a special type of bond only formed when a hydrogen atom is covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.