Question

Find the distance between two consecutive nodes if a string has tension 0.25 N, mass per unit length is 1 mg/m and frequency is 250 Hz.

• A. 2 m
• B. 1 m
• C. 3 m
• D. 1.5 M

Answer 1

Answer: (B)

1 m

Answer 2

The speed of transverse wave on the string will
be, $v=\sqrt{\frac{T}{m}}$
$v=\sqrt{\frac{0.25}{1\times10^{-6}}}$
$v = 500 \,m/sec$
and
$v = f \lambda$
So, $\lambda=\frac{500}{250}$
$\lambda=2$ m
Distance between two consecutive nodes is given by,
$=\frac{\lambda}{2}=1$ m
So, the correct option is (B) : 1 m.