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Question

Mathematics Question on introduction to three dimensional geometry

Find the distance between the points P(1,3,4)P(1, -3, 4) and Q(4,1,2)Q (-4,1,2).

A

5\sqrt{5} units

B

535\sqrt{3} units

C

35 3\sqrt{5} units

D

222\sqrt{2} units

Answer

35 3\sqrt{5} units

Explanation

Solution

The distance between the points P(1,3,4)P(1, -3, 4) and Q(4,1,2)Q(-4,1,2) is PQ=(41)2+(1+3)2+(24)2PQ = \sqrt{\left(-4-1\right)^{2}+\left(1+3\right)^{2}+\left(2-4\right)^{2}} =25+16+4=45= \sqrt{25+16+4}= \sqrt{45} =35= 3\sqrt{5} units