Question
Mathematics Question on introduction to three dimensional geometry
Find the distance between the points P(1,−3,4) and Q(−4,1,2).
A
5 units
B
53 units
C
35 units
D
22 units
Answer
35 units
Explanation
Solution
The distance between the points P(1,−3,4) and Q(−4,1,2) is PQ=(−4−1)2+(1+3)2+(2−4)2 =25+16+4=45 =35 units