Question
Physics Question on Dimensional Analysis
Find the dimensions of electric permittivity.
A
[A2M−1L−3T4]
B
[A2M−1L−3T0]
C
[AM−1L−3T4]
D
[A2M0L−3T4]
Answer
[A2M−1L−3T4]
Explanation
Solution
From Coulomb?? law, the force of attraction/repulsion between two point charges q, q separated by distance r is
F=4πε01r2q2
⇒ε0=4π1⋅Fr2q2
where e0 is electric permittivity.
Dimensions of ε0=[MLT−2][L2][AT]2
ε0=[A2M−1L−3T4]