Question
Question: Find the derivative of \[{\left( {3{x^2} - 7x + 3} \right)^{5/2}}\] with respect to \[x\]....
Find the derivative of (3x2−7x+3)5/2 with respect to x.
Solution
As the given equation is quadratic equation of the form ax2−bx+c, in which x is an unknown term and a function is said to be differentiable if its derivative exists and here we need to find the derivative with respect to x , hence differentiate the terms with dxd of each term as given in the equation.
Complete step by step answer:
We need to find the derivative with respect to x. The equation given is of the form ax2−bx+c in which to calculate the derivative of a sum, we simply take the sum of the derivatives.If we want to find the derivative of a difference, we simply find the difference of the derivatives.If we want to find the derivative of a product, we use the product rule for derivatives.As the given function is
f(x)=(3x2−7x+3)5/2
To find its derivative with respect to x let us write it in simplified manner
dxd(3x2−7x+3)5/2
Further simplifying the terms, we get
25(3x2−7x+3)5/2−1⋅dxd(3x2−7x+3)
Now let us expand the above terms with respect to x
25(3⋅dxd[x2]−7⋅dxd[x]+dxd[3])(3x2−7x+3)3/2
After derivative the terms with respect to x we get
25(3⋅2x−7⋅1+0)(3x2−7x+3)3/2
As we can see that the derivative of x2becomes 2x, derivative of xis 1 and derivative of 3 is 0.
Simplifying the terms, with respect to x we get
25(6x−7)(3x2−7x+3)3/2
⇒25(6x−7)(3x2−7x+3)3/2
Hence, after further simplification we get the final derivative as
∴2(30x−35)(3x2−7x+3)3/2
Therefore, this is the final derivative term with respect to x.
Note: To find any type of derivative with respect to x take dxd and with respect to ytake dyd . It is based on the derivative terms asked in the equation.Hence here are some the rules to find any kind of derivative asked: To find the derivatives of sum
[f(x)+g(x)]′=f′(x)+g′(x)
To find the derivatives of difference
[f(x)−g(x)]′=f′(x)−g′(x)
To find the derivatives of product
[f(x)⋅g(x)]′=f′(x)g(x)+g′(x)f(x)