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Question: Find the derivative of \[{\left( {3{x^2} - 7x + 3} \right)^{5/2}}\] with respect to \[x\]....

Find the derivative of (3x27x+3)5/2{\left( {3{x^2} - 7x + 3} \right)^{5/2}} with respect to xx.

Explanation

Solution

As the given equation is quadratic equation of the form ax2bx+ca{x^2} - bx + c, in which x is an unknown term and a function is said to be differentiable if its derivative exists and here we need to find the derivative with respect to xx , hence differentiate the terms with ddx\dfrac{d}{{dx}} of each term as given in the equation.

Complete step by step answer:
We need to find the derivative with respect to xx. The equation given is of the form ax2bx+ca{x^2} - bx + c in which to calculate the derivative of a sum, we simply take the sum of the derivatives.If we want to find the derivative of a difference, we simply find the difference of the derivatives.If we want to find the derivative of a product, we use the product rule for derivatives.As the given function is
f(x)=(3x27x+3)5/2f(x) = {\left( {3{x^2} - 7x + 3} \right)^{5/2}}

To find its derivative with respect to xx let us write it in simplified manner
ddx(3x27x+3)5/2\dfrac{d}{{dx}}{\left( {3{x^2} - 7x + 3} \right)^{5/2}}
Further simplifying the terms, we get
52(3x27x+3)5/21ddx(3x27x+3)\dfrac{5}{2}{\left( {3{x^2} - 7x + 3} \right)^{5/2 - 1}} \cdot \dfrac{d}{{dx}}\left( {3{x^2} - 7x + 3} \right)
Now let us expand the above terms with respect to xx
5(3ddx[x2]7ddx[x]+ddx[3])(3x27x+3)3/22\dfrac{{5\left( {3 \cdot \dfrac{d}{{dx}}\left[ {{x^2}} \right] - 7 \cdot \dfrac{d}{{dx}}\left[ x \right] + \dfrac{d}{{dx}}\left[ 3 \right]} \right){{\left( {3{x^2} - 7x + 3} \right)}^{3/2}}}}{2}

After derivative the terms with respect to xx we get
5(32x71+0)(3x27x+3)3/22\dfrac{{5\left( {3 \cdot 2x - 7 \cdot 1 + 0} \right){{\left( {3{x^2} - 7x + 3} \right)}^{3/2}}}}{2}
As we can see that the derivative of x2{x^2}becomes 2x2x, derivative of xxis 11 and derivative of 33 is 00.
Simplifying the terms, with respect to xx we get
5(6x7)(3x27x+3)3/22\dfrac{{5\left( {6x - 7} \right){{\left( {3{x^2} - 7x + 3} \right)}^{3/2}}}}{2}
52(6x7)(3x27x+3)3/2\Rightarrow\dfrac{5}{2}\left( {6x - 7} \right){\left( {3{x^2} - 7x + 3} \right)^{3/2}}
Hence, after further simplification we get the final derivative as
(30x35)(3x27x+3)3/22\therefore\dfrac{{\left( {30x - 35} \right){{\left( {3{x^2} - 7x + 3} \right)}^{3/2}}}}{2}
Therefore, this is the final derivative term with respect to xx.

Note: To find any type of derivative with respect to xx take ddx\dfrac{d}{{dx}} and with respect to yytake ddy\dfrac{d}{{dy}} . It is based on the derivative terms asked in the equation.Hence here are some the rules to find any kind of derivative asked: To find the derivatives of sum
[f(x)+g(x)]=f(x)+g(x)\left[ {f\left( x \right) + g\left( x \right)} \right]' = f'\left( x \right) + g'\left( x \right)
To find the derivatives of difference
[f(x)g(x)]=f(x)g(x)\left[ {f\left( x \right) - g\left( x \right)} \right]' = f'\left( x \right) - g'\left( x \right)
To find the derivatives of product
[f(x)g(x)]=f(x)g(x)+g(x)f(x)\left[ {f\left( x \right) \cdot g\left( x \right)} \right]' = f'\left( x \right)g\left( x \right) + g'\left( x \right)f\left( x \right)