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Question: Find the derivative of \( \left| {2{x^2} - 3} \right| \) with respect to \( x \) ....

Find the derivative of 2x23\left| {2{x^2} - 3} \right| with respect to xx .

Explanation

Solution

The sum rule and constant rule is applicable here. We need to differentiate the variable 2x22{x^2} and 33 differently by using different rules applicable to each of them.

Formula used: The formulae used in the solution are given here.
ddxnxa=naxa1\dfrac{d}{{dx}}n{x^a} = na{x^{a - 1}} where aa and nn are real numbers.
By sum rule, (αf+βg)=αf+βg\left( {\alpha f + \beta g} \right)' = \alpha f' + \beta g' for all functions ff and gg and for all real numbers α\alpha and β\beta .
By constant rule, if f(x)f\left( x \right) is a constant, then its derivative is f(x)=0.f'\left( x \right) = 0.

Complete Step by Step Solution
The function given here is f(x)=2x23f\left( x \right) = \left| {2{x^2} - 3} \right| .
Differentiation is the action of computing a derivative. The derivative of a function y=f(x)y = f\left( x \right) of a variable xx is a measure of the rate at which the value yy of the function changes with respect to the change of the variable xx . It is called the derivative of ff with respect to xx .
If xx and yy are real numbers, and if the graph of ff is plotted against xx , the derivative is the slope of this graph at each point.
To find the derivative, we differentiate f(x)f\left( x \right) with respect to xx .
f(x)=d(f(x))dx=ddx(2x23)f'\left( x \right) = \dfrac{{d\left( {f\left( x \right)} \right)}}{{dx}} = \dfrac{d}{{dx}}\left( {2{x^2} - 3} \right)
According to the sum rule, which states that, (αf+βg)=αf+βg\left( {\alpha f + \beta g} \right)' = \alpha f' + \beta g' for all functions ff and gg and for all real numbers α\alpha and β\beta .
We can write this in a simpler way as, ddx(2x2)ddx(3)=4x\dfrac{d}{{dx}}\left( {2{x^2}} \right) - \dfrac{d}{{dx}}\left( 3 \right) = 4x .
This is according to, ddxnxa=naxa1\dfrac{d}{{dx}}n{x^a} = na{x^{a - 1}} where aa and nn are real numbers.
By constant rule, if f(x)f\left( x \right) is a constant, then its derivative is f(x)=0.f'\left( x \right) = 0.
Thus, the value of ddx(3)\dfrac{d}{{dx}}\left( 3 \right) is zero, since 33 is a constant.

Note
Calculus, known in its early history as infinitesimal calculus, is a mathematical discipline focused on limits, functions, derivatives, integrals, and infinite series. Isaac Newton and Gottfried Leibniz independently discovered calculus in the mid-17th century. However, each inventor claimed the other stole his work in a bitter dispute that continued until the end of their lives.