Question
Question: Find the degree of association when \[1.0\] gram benzoic acid, dissolved in \[25\] gram benzene is h...
Find the degree of association when 1.0 gram benzoic acid, dissolved in 25 gram benzene is having depression in freezing point0.81K. The molal depression constant for solvent is 4.9K kg mole - 1
Solution
Hint : The number of moles of a specific substance associated per more of the substance taken is known as the degree of association.
Complete Step By Step Answer:
From the question it is clear that we should find the degree of association. It is clear from the question that 1.0 gram benzoic acid, dissolved in 25 gram benzene is having depression in freezing point0.81K. The molal depression constant is given in the question as 4.9K kgmole - 1. So firstly we are finding molar mass of benzoic acid.
Molar mass of Benzoic acid,
Initially, we were finding the molar mass of benzoic acid. Then we found the experimental molar mass of benzoic acid as242grammole−1. So here we are using the pre-defined equation of van’t Hoff factor (i) to find the degree of association. The factor I has a value less than 1 when the observed molecular mass is greater than the average. The Van't Hoff's factor is greater than 1 in the case of dissociation because the measured molecular mass is less than the normal molecular mass. In the absence of dissociation, the value of I becomes one. It is possible to calculate the degree of dissociation or association of a material using the value of ‘i.' And finally we found the degree of association as0.5.
Note :
The phenomenon of producing current carrying free ions that are dissociated from the fraction of solute at a given concentration is known as the degree of dissociation. The ratio between the actual concentration of particles formed when a substance is dissolved and the concentration of a substance measured from its mass is known as the Van 't Hoff factor.