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Question

Mathematics Question on Trigonometric Functions

Find the degree measures corresponding to the following radian measures (Use π=227).(\text{Use }π=\frac{22}{7}).

(i) 1116(ii)4(iii)5π3(iv)7π6.\text{(i) }\frac{11}{16} \,\text{(ii)} -4 \,\text{(iii)}\,\frac{5π}{3}\, \text{(iv)}\, \frac{7π}{6}.

Answer

(i)1116\text{(i)}\,\frac{11}{16}

We know that π radian = 180°

=1116radain=180π×1116degree=45×11πx4degree=\frac{11}{16} \,radain=\frac{180}{\pi}×\frac{11}{16}\text{degree}= \frac{45×11}{{\pi}x4}\text{degree}

=45×11×722×4degree=3158degree=\frac{45×11×7}{22×4}\text{degree}=\frac{315}{8}\text{degree}

3938degree39\frac{3}{8}\,\text{degree}

39°+3×608minutes....[1°=60]39^°+\frac{3×60}{8}\text{minutes}....[1^°=60']

=39°+22+12minutes=39^°+22'+\frac{1}{2}\,\text{minutes}

=39°2230.....[1=60]=39^°22'30''.....[1'=60'']


(ii)4\text{(ii)}\,-4

We know that π radian = 180°

4radian=180π×degree=229111degree-4\,radian=\frac{180}{\pi}×\text{degree}=-229\frac{1}{11}\text{degree}

=252011degree=229111.degree=\frac{-2520}{11}\,degree\,=-229\frac{1}{11}\\.degree

=229°+1×6011minutes....[1°=60]=-229^°+\frac{1×60}{11}\,minutes....[1^°=60']

=229°+5+511minutes=-229^°+5'+\frac{5}{11}\,\text{minutes}

=229°527.....[1=60]=-229^°5'27''.....[1'=60'']


(iii)5π3(iii)\,\frac{5\pi}{3}

We know that π radian = 180°

5π6 radian=180π×5π6degree=300°∴\frac{5{\pi}}{6} \text{ radian}=\frac{180}{\pi}×\frac{5{\pi}}{6}\text{degree}= 300°


(iv)7π6(iv)\,\frac{7\pi}{6}

We know that π radian = 180°

7π6 radian=180π×7π6degree=210°∴\frac{7{\pi}}{6}\text{ radian}=\frac{180}{\pi}×\frac{7{\pi}}{6}\text{degree}= 210°