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Question

Mathematics Question on Trigonometric Functions

Find the degree measure of the angle subtended at the centre of a circle of radius 100cm100 \,cm by an arc of length 22cm22 \,cm as shown in figure. [Use π=227\pi=\frac{22}{7}]

A

123012^{\circ}30'

B

123612^{\circ}36'

C

113611^{\circ}36'

D

111211^{\circ}12'

Answer

123612^{\circ}36'

Explanation

Solution

Given radius, r=100cmr = 100\,cm and arc length, I=22cmI = 22 \,cm We know that, l=rθl = r\theta θ=lr=Arc lengthRadius=22100\theta=\frac{l}{r}=\frac{\text{Arc length}}{\text{Radius}}=\frac{22}{100} =0.22rad=0.22 \,rad =0.22×180π=0.22\times\frac{180}{\pi} degree =0.22×180×722=0.22\times\frac{180 \times 7}{22} =12610=12610=\frac{126^{\circ}}{10}=12 \frac{6^{\circ}}{10} =12+610×60[1=60]=12^{\circ}+\frac{6}{10}\times60'\,\left[\because 1^{\circ}=60'\right] =12+36=1236=12^{\circ}+36'=12^{\circ}\,36' Hence, the degree measure of the required angle is 123612^{\circ}36'.