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Question: Find the current in the three resistors in figure. ![](https://www.vedantu.com/question-sets/c917...

Find the current in the three resistors in figure.

Explanation

Solution

To solve circuit-based questions we have to know the concepts and applications of KVL and KCL. Name the ends of the circuits as ABCDEFGH. Let us consider a current ii coming out from the lower left most cell of the circuit AB and then dividing into i1{i_1} andii1i - {i_1} at point G. Now let i1{i_1} be again divided into part i1{i_1} and i1i2{i_1} - {i_2} at the point F.

Complete step by step answer:

Considering loop AHGBA:
2+(ii1)2=0 ii1=0. 2+(ii1)2=0 ii1=02 + (i - {i_1}) - 2 = 0 \\\ \Rightarrow i - {i_1} = 0. \\\ \Rightarrow 2 + (i - {i_1}) - 2 = 0 \\\ \Rightarrow i - {i_1} = 0
Thus i=i1i = {i_1} . (1) - - - - (1)
Considering loop BGFCB:
2(ii1)2+i1i2=02 - (i - {i_1}) - 2 + {i_1} - {i_2} = 0
(ii1)+i1i2=0\Rightarrow (i - {i_1}) + {i_1} - {i_2} = 0
But we know that i=i1i = {i_1} , hence the first term gets cancelled.
Thus, i1=i2{i_1} = {i_2} (2) - - - - (2)
Considering loop CFEDC, we get
2 + {i_2} - ({i_1} - {i_2}) - 2 = 0 \\\
2i2i1=0\Rightarrow 2{i_2} - {i_1} = 0 (3) - - - - (3)

Now compare equation 2 and equation 3, we see that the value is only possible when both i1,i2{i_1},{i_2} are zero. Thus we can also confirm that i = 0i{\text{ = 0}}.Now lets see the current through resistors:
For R1R_1: current is ii1i - {i_1} , but from (1) we see the value is zero. Hence current through R1R_1 is zero.
For R2R_2: current is i1i2=0{i_1} - {i_2} = 0, but from (2) we see the value is zero. Hence current through R2R_2 is zero. Similarly, for R3R_3 we see that the value of current through the resistance is zero.

Hence no current passes through these three resistances.

Additional information: KVL: The law which deals with the conservation of energy for a closed circuit path. The law states that for a closed loop path the algebraic sum of all the emf around any closed loop in a circuit is equal to zero.

Note: From these types of questions it is to be kept in mind that if equal and opposite emf are applied in a circuit, then no current flows through the circuit. Thus we can now apply this concept to other questions where there may be any number of resistances and emf.