Question

Find the cost of polishing a circular table-top of diameter $1.6$ $m$, if the rate of polishing is Rs $15/m^2$ . (Take $\pi$ = $3.14$)

Answer 1

Diameter = $1.6$ $m$
Radius = $\frac{1.6}{2}$
= $0.8$ $m$
Area = $3.14 × 0.8 × 0.8$
= $2.0096 \;m^2$
Cost for polishing $1$ $m^2$ area = Rs $15$
Cost for polishing $2.0096$ $m^2$ area = $15 × 2.0096$ = $30.14$

Therefore, it will cost Rs $30.14$ for polishing such circular table.