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Question

Question: Find the coordinates of the point which divides the line segment joining \(( - 1,3)\) and \((4, - 7)...

Find the coordinates of the point which divides the line segment joining (1,3)( - 1,3) and (4,7)(4, - 7) internally in the ratio 3:4.3:4.

Explanation

Solution

Hint-In order to solve such a question we will simply use the section formula which tells us the coordinates of the point which divides a given line segment into two parts such that their length is in the ratio m:n.
[mx2+nx1m+n,my2+ny1m+n]\left[ {\dfrac{{m{x_2} + n{x_1}}}{{m + n}},\dfrac{{m{y_2} + n{y_1}}}{{m + n}}} \right]
Where m, n is the ratios and x, y is the coordinates.

Complete step-by-step answer:

We will solve the problem with the help of a given figure.
As we know that section formula or required coordinates of the point is given as
[mx2+nx1m+n,my2+ny1m+n]\left[ {\dfrac{{m{x_2} + n{x_1}}}{{m + n}},\dfrac{{m{y_2} + n{y_1}}}{{m + n}}} \right]
Given ratio is 3:43:4 and the coordinates of the line are (1,3)( - 1,3) and (4,7)(4, - 7) .
So, here m=3,n=4m = 3,n = 4 and x1=1,y1=3,x2=4,y2=2{x_1} = - 1,{y_1} = 3,{x_2} = 4,{y_2} = - 2
Substituting these values in the section formula given above, we get

(mx2+nx1m+n,my2+ny1m+n) (3×4+4×(1)3+4,3×(7)+4×33+4) (1247,21+127) (87,97)  \Rightarrow \left( {\dfrac{{m{x_2} + n{x_1}}}{{m + n}},\dfrac{{m{y_2} + n{y_1}}}{{m + n}}} \right) \\\ \Rightarrow \left( {\dfrac{{3 \times 4 + 4 \times ( - 1)}}{{3 + 4}},\dfrac{{3 \times ( - 7) + 4 \times 3}}{{3 + 4}}} \right) \\\ \Rightarrow \left( {\dfrac{{12 - 4}}{7},\dfrac{{ - 21 + 12}}{7}} \right) \\\ \Rightarrow \left( {\dfrac{8}{7},\dfrac{{ - 9}}{7}} \right) \\\

Hence, the coordinates of the point which divides the line segment joining (1,3)( - 1,3) and (4,7)(4, - 7) internally in the ratio 3:43:4is (87,97)\left( {\dfrac{8}{7},\dfrac{{ - 9}}{7}} \right).

Note- To solve these types of problems remember all the formulas of coordinate geometry. And try to draw a rough sketch of the diagram on the paper, this helps a lot in solving the question. Graphs method is always the easiest and least time consuming method.