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Question

Mathematics Question on Parabola

Find the coordinates of the focus, the axis of the parabola, the equation of directrix, and the length of the latus rectum for y2=8xy^2 = - 8x

Answer

The given equation is y2=8xy^2= -8x.
Here, the coefficient of x is negative. Hence, the parabola opens towards the left.
On comparing this equation with y2=4ax,y^2= -4ax, we obtain
4a=8-4a= -8

a=2⇒ a = 2

∴Coordinates of the focus = (a,0)=(2,0)(-a, 0) = (-2, 0) Since the given equation involves y2y^2, the axis of the parabola is the x-axis.
Equation of directrix, x=ax= a

i.e.,x=2,x = 2

The length of the latus rectum is 4a=84a= 8 (Ans.)