Question
Question: Find the compound interest on \[{\text{Rs}}.48000\] for \[2{\text{ yrs}}\] compounded annually at \[...
Find the compound interest on Rs.48000 for 2 yrs compounded annually at 221% per annum.
Solution
Here we will be using the formula of compound interest which states as below:
A=P(1+nr)nt , where
A=final amount,
P=initial principal balance,
r=rate of interest,
n=no.of time interest applied and
t=number of time periods.
Complete answer:
Step 1: As given in the question
P=48000,
r=25% ,
t=2 yrs and
n=1. By substituting these values in the formula
A=P(1+nr)ntwe get:
A=48000(1+15/2)1×2
By solving inside the brackets in the RHS side of the above expression, we get:
⇒A=48000(1+0.025)2
By doing addition inside the brackets in the RHS side of the above expression, we get:
⇒A=48000(1.025)2
By solving the powers and multiplying
1.025×1.025, on the RHS side we get:
⇒A=48000(1.050625)
After doing the final multiplication in the RHS side of the above expression, we get:
⇒A=Rs. 50430
Step 2: Now, as we know interest equals the subtraction of principal amount from total amount i.e. ⇒Interest=A−P.
By substituting the values of P=48000 and A=50430 in the RHS side of the above expression we get:
⇒Interest=50430−48000
By doing the subtraction in the RHS side of the above expression we get:
⇒Interest=Rs. 2430
Interest amount is Rs. 2430.
Note:
Students need to remember the difference between the Simple interest and compound interest formulas. Simple interest is calculated on the principal amount. Compound interest is calculated on the principal amount and also on the accumulated interest of previous periods, which is known as interest on interest. Also, students need to know that the formula which we are using is for calculating the amount, not compound interest. Compound interest is the difference between the amount and principal value.