Solveeit Logo

Question

Question: Find the common ratio of the geometric sequence: \( - 1,1, - 1,1...........\) \( {\text{a}}{\t...

Find the common ratio of the geometric sequence: 1,1,1,1........... - 1,1, - 1,1...........
a. 1 b. 1 c. 2 d. 2  {\text{a}}{\text{. 1}} \\\ {\text{b}}{\text{. }} - 1 \\\ {\text{c}}{\text{. 2}} \\\ {\text{d}}{\text{. }} - 2 \\\

Explanation

Solution

Hint: - Use common ratio of a G.P =an+1an = \dfrac{{{a_{n + 1}}}}{{{a_n}}}.
Given geometric series is 1,1,1,1........... - 1,1, - 1,1...........

As we know for a G.P say (a1,a2,a3,a4,............an,an+!)\left( {{a_{1,}}{a_{2,}}{a_{3,}}{a_{4,}}............{a_n},{a_{n + !}}} \right) the common ratio (r)\left( r \right) is written as
r=a2a1=a3a2=a4a3=..........an+1anr = \dfrac{{{a_2}}}{{{a_1}}} = \dfrac{{{a_3}}}{{{a_2}}} = \dfrac{{{a_4}}}{{{a_3}}} = ..........\dfrac{{{a_{n + 1}}}}{{{a_n}}}

Where (n=1,2,3..............)\left( {n = 1,2,3..............} \right)

So, the common ratio (r)\left( r \right)for the given series isr=11=11=11=1r = \dfrac{1}{{ - 1}} = \dfrac{{ - 1}}{1} = \dfrac{1}{{ - 1}} = - 1
Hence option (b) is correct.

Note: - In such types of questions the key concept we have to remember is that always remember the formula of common ratio of a G.P which is stated above, then simplify we will get the required common ratio of a G.P.