Question
Question: Find the charge on each capacitor during steady state- 
A
3µC
B
6µC
C
9µC
D
12µC
Answer
12µC
Explanation
Solution
I=
=510= 2A; \VA – VB = IR = 2 × 4 = 8 V
\P.D across each capacitor is 4 V hence q = 4 × 3 = 12 µC
