Question
Question: Find the area of the given triangle whose angles are \[{30^ \circ },{60^ \circ },{90^ \circ }\]?...
Find the area of the given triangle whose angles are 30∘,60∘,90∘?
Solution
For finding the area of a given triangle you need to have the measurement of the sides, which can be calculated by the given angles or of given in the question already. For finding the sides you have to use the trigonometry identity to find the values as we already know the trigonometry values for a given angle.
Formulae Used: Area=21×base×height,tanθ=baseperpendicular,tan60=3
Complete step by step solution:
The given angles are 30∘,60∘,90∘
Let's draw a triangle with the given angles and assume variables for the length of sides which needed to be obtained for further finding the area of the triangle:
For the above triangle area of the triangle can be find by using formula:
21×base×height
Here base of the triangle is “CB” whose length is “c” and height of the triangle is “AC” whose length is “b”
To find both the length we can use:
tanθ=baseperpendicular=CBAC(forourgiventriangle)
Here the value of angle θ is “60 degree”
Now using above formulae we get;
tan60=CBAC 3=CBAC(tan60=3) weget;AC=3andCB=1;oncomparisononbothsidesofequationSo area of the given triangle is:
Area=21×base×height Area=21×AC×CB Area=21×3×1 Area=21.731(3=1.732) Area=0.866squnitsOur required area for the given triangle is 0.866squnits.
Note: Here we are to use the “sin” values to find the measurement of the sides but you can use any other trigonometric identity according to your ease. The only result we want is the measurement of the sides; it is up to us how we are going to find it and which identity suits best according to the data given in the question.